Integrand size = 29, antiderivative size = 23 \[ \int \frac {x^{\frac {1-n}{2}+\frac {1}{2} (-3+n)}}{\sqrt {a+b x}} \, dx=-\frac {2 \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{\sqrt {a}} \]
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Time = 0.01 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {7, 65, 214} \[ \int \frac {x^{\frac {1-n}{2}+\frac {1}{2} (-3+n)}}{\sqrt {a+b x}} \, dx=-\frac {2 \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{\sqrt {a}} \]
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Rule 7
Rule 65
Rule 214
Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{x \sqrt {a+b x}} \, dx \\ & = \frac {2 \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x}\right )}{b} \\ & = -\frac {2 \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{\sqrt {a}} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.00 \[ \int \frac {x^{\frac {1-n}{2}+\frac {1}{2} (-3+n)}}{\sqrt {a+b x}} \, dx=-\frac {2 \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{\sqrt {a}} \]
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Time = 0.06 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.78
method | result | size |
derivativedivides | \(-\frac {2 \,\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{\sqrt {a}}\) | \(18\) |
default | \(-\frac {2 \,\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{\sqrt {a}}\) | \(18\) |
pseudoelliptic | \(-\frac {2 \,\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{\sqrt {a}}\) | \(18\) |
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none
Time = 0.23 (sec) , antiderivative size = 56, normalized size of antiderivative = 2.43 \[ \int \frac {x^{\frac {1-n}{2}+\frac {1}{2} (-3+n)}}{\sqrt {a+b x}} \, dx=\left [\frac {\log \left (\frac {b x - 2 \, \sqrt {b x + a} \sqrt {a} + 2 \, a}{x}\right )}{\sqrt {a}}, \frac {2 \, \sqrt {-a} \arctan \left (\frac {\sqrt {b x + a} \sqrt {-a}}{a}\right )}{a}\right ] \]
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Time = 0.80 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.04 \[ \int \frac {x^{\frac {1-n}{2}+\frac {1}{2} (-3+n)}}{\sqrt {a+b x}} \, dx=- \frac {2 \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} \sqrt {x}} \right )}}{\sqrt {a}} \]
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Time = 0.30 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.39 \[ \int \frac {x^{\frac {1-n}{2}+\frac {1}{2} (-3+n)}}{\sqrt {a+b x}} \, dx=\frac {\log \left (\frac {\sqrt {b x + a} - \sqrt {a}}{\sqrt {b x + a} + \sqrt {a}}\right )}{\sqrt {a}} \]
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none
Time = 0.29 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.91 \[ \int \frac {x^{\frac {1-n}{2}+\frac {1}{2} (-3+n)}}{\sqrt {a+b x}} \, dx=\frac {2 \, \arctan \left (\frac {\sqrt {b x + a}}{\sqrt {-a}}\right )}{\sqrt {-a}} \]
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Time = 0.00 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.74 \[ \int \frac {x^{\frac {1-n}{2}+\frac {1}{2} (-3+n)}}{\sqrt {a+b x}} \, dx=-\frac {2\,\mathrm {atanh}\left (\frac {\sqrt {a+b\,x}}{\sqrt {a}}\right )}{\sqrt {a}} \]
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